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I=['daddy']; I.concat(['gineer', 'trepreneur'].map(x => 'en'+x))

console.log(null || undefined || 0 || '?')

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THANK YOU!!! Sponsor @june07 on GitHub SponsorsSupport Node.js (JavaScript V8 Engine... Deno, etc.) developer tooling. NiM, BrakeCODE, and associated tools.GitHubDonate to June07Help support June07 by donating or sharing with your friends. bitcoin: bc1q4kwrjnx3h0v894vlp6d9l3efwv0jtddnjukrpm ethereum: 0x69F3C9210091A0E5cb7D01459683447173D4BDDA
Oct 11, 2023 1 min read
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